Quote (Godzillatoss @ Mar 7 2014 06:45pm)
1. read the edit
2. I know how to do some like:
Propene = CH2=CH2CH3
Ethanol = CH3CH2OH
But i dont know how you would represent an ester! how you would put it into this form since the C is attached to a double bonded O and the alcohol
Think of acetic acid. Not quite an ester, but carboxylic acids are close enough to be used as approximations. CH3COOH
By having the -COOH at the end, people can safely assume it's a carboxylic acid (since peroxyacids are notoriously unstable).
By that logic, if I was working with methyl ethanoate, I'd represent it as CH3COOCH3.
The likelihood of that being a random peroxy- group in there are essentially zero, and because the methyl carbon has three hydrogens on it already, you can deduce that it doesn't have a double bonded oxygen attached.
This post was edited by Mikhail on Mar 12 2014 12:19am