d2jsp
Log InRegister
d2jsp Forums > Off-Topic > General Chat > Homework Help > One-to-one Function
Add Reply New Topic New Poll
Member
Posts: 2,575
Joined: Jul 31 2006
Gold: 0.00
Mar 6 2014 10:08pm
This seems so easy, but I can't figure it out.

Determine whether the function is one-to-one

f(x) = x^4 + 5
Member
Posts: 16,796
Joined: Oct 15 2008
Gold: 19,640.61
Mar 6 2014 10:24pm

is it asking that the range and the domain are unique? Meaning for every x there is a unique f(x), and for every finverse(x) you get back the original x and no more?

Member
Posts: 10,812
Joined: Oct 15 2009
Gold: Locked
Warn: 20%
Mar 6 2014 10:25pm
f(-1) = 6
f(1) = 6

clearly not one to one
----------------
or more formally

f(a) = f(b)
a^4 + 5 = b^4 + 5

a^4 = b^4

a = +/- b

again, clearly not 1 to 1
Member
Posts: 2,575
Joined: Jul 31 2006
Gold: 0.00
Mar 6 2014 10:26pm
Quote (Azrad @ Mar 6 2014 10:25pm)
f(-1) = 6
f(1) = 6

clearly not one to one
----------------
or more formally

f(a) = f(b)
a^4 + 5 = b^4 + 5

a^4 = b^4

a = +/- b

again, clearly not 1 to 1


lol I swear I tried that...thanks as always man!
Member
Posts: 28,331
Joined: Jun 9 2007
Gold: 11,700.00
Mar 6 2014 11:11pm
Quote (JoeyMorgan619 @ 7 Mar 2014 04:08)
This seems so easy, but I can't figure it out.
Determine whether the function is one-to-one
f(x) = x^4 + 5


you got the answer but let me give you a hint:
for polynomial functions having as domain the whole real line
those of an even degree are never one-to-one
Member
Posts: 10,812
Joined: Oct 15 2009
Gold: Locked
Warn: 20%
Mar 6 2014 11:17pm
Quote (brmv @ Mar 6 2014 10:11pm)
you got the answer but let me give you a hint:
for polynomial functions having as domain the whole real line
those of an even degree are never one-to-one


yeah anytime you beat on one of these even power ones, you'll always encounter the problem above, a +/- will creep in, ruining everything
Go Back To Homework Help Topic List
Add Reply New Topic New Poll