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Feb 23 2014 02:35pm
Hey guys,

I have a good number of problems here. I figured I would put all of the ones I couldn't figure out. Some of them are really similar, so just getting one worked out would be good enough for me to get the rest. Any help would be appreciated.







http://i12.photobucket.com/albums/a207/aaronisjoey/11.png

http://i12.photobucket.com/albums/a207/aaronisjoey/domains.png
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Feb 23 2014 06:05pm
I didn't actually mean to put the very first picture on there. I got that already.
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Feb 23 2014 08:50pm
doman u just set the expression under the radical to greater/equal to zero and look for the range of values tat fit
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Feb 23 2014 10:39pm
To restate: The domain is the set of values that are acceptable for x. Or in other words, start with the domain equal to all real numbers, then remove numbers from that list that would "break the function. Some things to look for are:

  • A value for x that would make a denominator equal to zero.
  • A value for x that would put you into a situation where you would need the square root of a negative number.
  • A value for x that would cause you to try to take the log of zero or a negative number.

So if you see any fractions, square roots, or logs, you can either just find the bad values for x by inspection (just looking at it and realizing what it is), or you can do something like:
Say you have a denominator that is "2x + 6", we know that can't be zero from the rules above so we do this:

2x + 6 ≠ 0
Then just "solve" that for x:

2x ≠ -6

x ≠ -3

And that is your domain, x ≠ 3; as that would "break" the function.
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