Quote (cialda @ Feb 11 2014 09:09pm)
is the "m" molality or molarity?
also what level class is this? in an ideal solution, the van't hoff factor should just be 2 iirc.
for non ideal, i believe it should be:
(Pnot - P)/Pnot = i*mole fraction
Pnot = vapor pressure pure solvent
P = vapor pressure of the resulting solution
i = van't hoff factor
mole fraction = mole solute/total mole
(Pnot - P)/Pnot = i*mole fraction
Pnot = 23.76
P = 23.76 - 0.734
i = unknown
mole fraction solute = mole solute/total mole
1 molality = 1 mole KCl / 1000 g H2O
1000 g H2O = 55.56 mole h2o
mole fraction = 1/(55.56+1) ~= 0.0177
((Pnot - P)/Pnot)/mole fraction = 1.747
another way to do it:
Mole fraction solute calculated (theoretical) = 1/56.56 = 0.0177
P = Pnot *mole fraction solvent
P/Pnot = 0.969 = mole fraction solvent
1 = mole fraction solvent + mole fraction solute
mole fraction solute = 1 - mole fraction solvent = 0.0309
i (vant hoff factor) = observed colligative value / calculated value with no association/dissociation
i = 0.0309 / 0.0177 = 1.747
hopefully this helps. not too familiar with these formulas myself.
This post was edited by cialda on Feb 11 2014 10:03pm