Quote (Pindrought @ Feb 10 2014 06:58pm)
I am getting sin(x)^2 for when I do u=sinx
However, i've come to the conclusion that this answer is wrong.
Here is why.
When I put in the integral to solve on wolframalpha, I get that the answer is -cos(x)^2
I am getting -cos(x)^2 for when I do u=cosx
( Note: -cos(x)^2 = -(1/2)cos(2x) )
If sin(x)^2 = -cos(x)^2 then that should mean thatsin(x)^2 + cos(x)^2 = 0 correct?
The issue is that sin(x)^2+cos(x)^2 = 1, it doesn't = 0 so they can't be equal.
Am I misunderstanding something or am I going crazy or what?
the way you're trying to compare them can't be done.
You can't leave off the "+c" terms when setting them equal to each other.
They are equal to each other through trig identities, so when you get answers like this, always tweak with identities to try and get the answers the same
But yes, doing it that way you tried it works as well, AS LONG as you keep the "+c" in both of your answers.
So,
(sin x)^2 + c = -(cos x)^2 + c (note that both c's are NOT necessarily equal)