Quote (fingerling @ 26 Jan 2014 23:20)
How do I solve this:
4/x / 4/x+1
4 over x. Over. 4 over x +1
Also this one guys:
3(x-8/3)+8
I realize these are simple but its been forever since I had algebra.
The second one is x-8 over 3. I wasn't sure how to distribute this because I was thinking 3 x all to get 3x-24/9 but the book is telling me my answer ends up as x. Just x.
as said before, you have to learn to write the formulae tidy, i guess what you mean is:
(4/x) / (4/[x+1]) -> (4/x)*([x+1]/4) -> (x+1)/x
and 3([x-8]/3)+8 -> [x-8]+8 -> x
see how writing it in a proper fashion does make it easier?
This post was edited by brmv on Jan 26 2014 05:34pm