need to integrate this: (x^2)((x+8)^(1/2))dx

let

u = x + 8
du = dx

so x = u - 8

your integral is now

(u - 8)^2*sqrt(u) du

expand (u-8)^2: ---> u^2 - 16u + 64

multiply every term separately by sqrt(u) which is equivalent to u^(1/2)

your new integral is: u^(5/2) - 16u^(3/2) + 64u^(1/2) du

you should have no problem integrating that.

don't forget to plug back u = x + 8 to have an answer in terms of x

This post was edited by rx7drifter on Jan 21 2014 10:12pm

thanks, I figured this out before I checked back here, but thank you for helping and confirming that my answer was correct.