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Jan 21 2014 06:20pm
What is the equation of the line that satisfies these conditions?

Thru (−4, 6) and parallel to the line x = 1

This post was edited by JoeyMorgan619 on Jan 21 2014 06:24pm
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Jan 21 2014 06:23pm
Quote (JoeyMorgan619 @ 22 Jan 2014 00:20)
What is the equation of the line that satisfies these conditions?
Through points (−4, 6) and parallel to the line x = 1


you mean the point (-4,6)?
and if that is the case it would be the line having x=-4
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Jan 21 2014 06:24pm
Quote (brmv @ Jan 21 2014 06:23pm)
you mean the point (-4,6)?
and if that is the case it would be the line having x=-4


yeah my bad
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Jan 22 2014 01:54am
Nvm

This post was edited by fingerling on Jan 22 2014 02:13am
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Jan 22 2014 02:05am
Quote (fingerling @ Jan 22 2014 02:54am)
Y= -6/5x + 1 1/3

I think


parallel lines have the same slope. does that have the same slope as x = 1?
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Jan 22 2014 02:21am
Quote (carteblanche @ Jan 22 2014 01:05am)
parallel lines have the same slope. does that have the same slope as x = 1?


kind of, heh. This problem is kind of a gotcha. The slope of the line x = 1 is undefined. (change in y)/(change in x), and in this case x does not change, so the slope calculation has a divide by zero problem.
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Jan 22 2014 05:15am
Quote (Azrad @ Jan 22 2014 10:21am)
kind of, heh. This problem is kind of a gotcha. The slope of the line x = 1 is undefined.  (change in y)/(change in x), and in this case x does not change, so the slope calculation has a divide by zero problem.


equation is actually not y = a*x + b but a*x + b*y + c = 0 (particularly because of what you said)
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