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#1
Dec 10 2013 04:10pm
Question: How many distinct arrangements can be made of the letters in the word CONNECTICUT?

if any1 knows this please help
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#2
Dec 10 2013 04:46pm
The formula to calculate that is n!/(k1!*k2!...kt!) where n is the amount of objects and the first object appears k1 times, the second object k2 times and so on.

So for Connecticut, n = 11 (because there are 11 letters) k1 = 3, k2 = 1 and so on.

This post was edited by Molle_fkk on Dec 10 2013 04:46pm
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#3
Dec 10 2013 04:47pm
e/nvm

This post was edited by Sefira on Dec 10 2013 04:47pm
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#4
Dec 10 2013 05:40pm
Quote (Molle_fkk @ 10 Dec 2013 22:46)
The formula to calculate that is n!/(k1!*k2!...kt!) where n is the amount of objects and the first object appears k1 times, the second object k2 times and so on.

So for Connecticut, n = 11 (because there are 11 letters) k1 = 3, k2 = 1 and so on.


ts, ts,ts

3 * C
2 * N & T
1 * E, I, O & U
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#5
Dec 10 2013 05:49pm
Quote (brmv @ Dec 10 2013 05:40pm)
ts, ts,ts

3 * C
2 * N & T
1 * E, I, O & U


Yeah as in the second letter, O, is k=1.
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