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#1
Dec 8 2013 12:47pm
If I set sqrt-of-alpha(x) as n*x

and i moved n around my equation, till it turned out at b*n*a (a,b = constants), retranslating the n would then be sqrt-of-alpha(a*b), or b*[sqrt-of-alpha(a)]?
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#2
Dec 8 2013 01:05pm
b*[sqrt-of-alpha(a)]
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#3
Dec 8 2013 02:37pm
ty :3
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