Done, thanks.

This post was edited by Stolem on Nov 26 2013 03:39pm

#5

E=F/q

F=kq1q2/r^2

(kq1q2/r^2)/q=kq/r^2 ------------> because the q's cancel out

E=kq/r^2

k=9e+9

q(proton)=1.602e-19

2.2e+5=(9e+9)(1.602e-19)/r^2
just solve for r, easy right?

r=8.095e-8m

#2
F = k*q^2/r^2 = 9.0x10^9*(6*1.60x10^-19)^2/(0.15x10^-9)^2 = 3.69x10^-7N

This post was edited by JDota72 on Nov 26 2013 03:30pm

#1.
E = F/q
F = kq1q2/r^2
or just E = kq/r^2

K = 9.0 x 10^9 Nm^2/C^2

r = (9.0 x 10^9 Nm^2/C^2) x (1.6 x 10^-19 C) / (2.8 x 10^5 N/C)^(1/2)
Do the math cross out what you need, I don't know if it's 105 or 10^5, should be 10^5, but you should do it yourself either way.

#2. F = kq^2/r^2
K = 9.0x10^9 Nm^2/C^2
F = 9.0x10^9 x (6 x1.60x10^-19)^2/(0.15x10^-9)^2

This post was edited by Sefira on Nov 26 2013 03:36pm