been 2 years since high school and forgot how to do this

Expand

-3a(a-3b^2)(a+3b^3)(a^2+9b^4)(a^4+81b^8)

you have to multiply each term from each paranthesis with each other, eg (a+b)(c-d)=ac-ad + bc-bd
so let's start:

-3a(a-3b^2)(a+3b^3)(a^2+9b^4)(a^4+81b^8)=(-3a^2+9ab^2)(a+3b^3)(a^2+9b^4)(a^4+81b^8)=

(-3a^3-9a^2b^3+9a^2b^2+27ab^5)(a^2+9b^4)(a^4+81b^8)

the rest should be easy (though tedious) for you to fix

This post was edited by brmv on Nov 17 2013 08:47pm

thx! wish I had some fg to tip for your time

thx but no need, was not a colossal task
hope everything is clear now