I'm supposed to "If Y follows a continuous uniform distirbution from A to B, show that E(Y) = (A+B)/2"

As with any proof, I have no idea where to start.
I'm assuming it's something about an integral from A to B, but I don't know what I'm integrating to start =/

Thanks for any help.

An integral, indeed.

Since Y follows a continuous uniform distribution, its probability density function is : 1/ (B-A).

The expected value, therefore, is :

E(Y) = Integral from A to B of x*[ 1 / (B-A) ].dx

And since the density function is a linear function, it should be easy to find out how much E(Y) is !

Ah thank you!
I already did this problem once a couple weeks ago, but I couldn't remember how to start it this time xD