A negative charge q= −3.40×10−6C is located at the origin and has velocity υ⃗ =(7.50×104m/s)i+((−4.90)×104m/s)j

At this instant what is the magnetic field produced by this charge at the point x = 0.120m , y = -0.310m , z = 0? IN μT
Enter the x, y, and z components of the magnetic field separated by commas.

you're already, given velocity components so you can straight plug into

B= (u_0)qv/(4*pi*r^2)

B field is in direction of v cross directional vector ( test charge, that concept , not direction of the charge)
perpendicular of v and test point

This post was edited by saber_x3 on Nov 12 2013 10:32pm