@1: f(x)=x^1171 - 5*x^109 would be origin symmetric because it is odd and f(-x)=-f(x) but the +3 shifts the function away from the origin so the answer is 'neither one'

f-1(x) != 1 / f(x)

the method for finding an inverse function most often taught is to

solve for x
"switch" the y and x

y= is your inverse

ex
y = 2x + 2

y-2 = 2x
x = (y-2) / 2

switch

y = (x-2) / 2

what # is this

its for the ones asking for an inverse


for a 1-to-1 function, it needs to have "element of the range of the function corresponds to exactly one element of the domain."

Here is a little example of someone determining whether a function is 1-to-1



In your case, your g(x) would be the equation in #5.

This post was edited by khemist on Nov 11 2013 11:00pm

thanks!

anyone else?

#7
a) the minus sign on the x^2 term means it opens downward

b.) a parabola is symmetric around a vertical line through its vertex:
x = -b/2a ---> x = -(-2)/[(2)*(-1)] = 2/-2 = -1
x = -1

c) well we know the x coordinate is -1 from part b, so just plug that into the equation to get the y value:
y = -(-1)^2 - 2(-1) + 15 = -1 + 2 + 15 = 16
so the point is {-1,16}

d) at the y intercept, x = 0, so lets just plug in x = 0 into the parabola:
y = -(0)^2 - 2(0) + 15 = 15
{0,15}

e) at the x intercept(s), y = 0, so lets just plug that into the parabola:
0 = -(x)^2 - 2(x) + 15; using quadratic formula gives:
x = -5, 3
{-5,0}, {3,0}

f) heh I'll leave the graph to you, just plot the points above and connect the dots with a nice curve

This post was edited by Azrad on Nov 12 2013 10:27am

how much fg do u want

oh don't worry about it