Get 100 fg per question (must answer all parts of the question)
Show all work, including the used equation and the final answer.

1a) average acceleration : a = (v2-v1)/(t2-t1) = (20-10)/5 = 2m.s^-2
1b) constant acceleration of 2m.s^-2 -> speed v(t) = 10+2t, position is x(t) = 10t+t^2, so after 5 seconds, the car travelled 75m
1c) highest average acceleration : t = 4.9s, v1 = 9.9, v2 = 20.1. In this case, a1 = 2.08m.s^-2
lowest average acceleration : t = 5.1s, v1 = 10.1, v2 = 19.9. In this case, a2 = 1.92
Hence the uncertainty is : u = +/- 0.8m.s^-2

no time for the rest right now

These are basic physics questions. If you have any hope of passing your physics course, i would attempt to do these on your own.

know your kinematics and that would solve half your issue here. Know conservation of energy and how to sum forces.

Another useful equation in this case would be E-gm1m2/r and rcm= ((m*x)1+(m*x)2)/m1+m2

To me the only tricky one should be the last one. IF you figure out the first two try and do the last one. If you can figure it out ill help you with it

I did. I do this to double check.



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This post was edited by gthe91 on Oct 27 2013 04:09pm

since you did it I won't remake it neatly

One of the equations as the top is to be ignored and the scribbling too.

i rather post link rather than image

http://imageshack.us/photo/my-images/31/lnsd.jpg

i'll look at #3

This post was edited by rx7drifter on Oct 27 2013 04:06pm

I actually wasn't sure on how to do part B, but did you do that on paper and then scan it?

I just had someone PM me the last question.
So this is done, unless rx7drifter has already started doing it, I'll give him 50 fg so his effort isn't wasted.





This post was edited by gthe91 on Oct 27 2013 04:24pm

i gladly did not start

and yes i did scan it

This post was edited by rx7drifter on Oct 27 2013 04:23pm