Purpose: Use arrays & strings.

Description:

Write a function that determines if a string contains a
single word palindrome.

Pass a string to the function and have it return true or
false indicating whether the string contains a single
word palindrome.


Okay so here is where i am at.
I have a function to check for palindrome but now I need to have one function that tests a whole phrase instead of just a word which means i need it to ignore spaces and caps.


Below is the code I have that tests for palindrome although it doesnt ignore spaces or caps which is where i guess i need help.
void pal(char *str1)
{
int i;
int x;
x = strlen(str1)-1;
for ( i = 0; i<=x; i++)
{
if(str1[i] == str1[x-i])
{
printf(" Your String is a Palindrome \n");
return 0;
}
else
{
printf(" Your String is not a Palindrome \n");
return 0;
}
}
}


In the end goal is to have one functions that tests a phare for palindrome and ignores spaces and caps.

[I]void pal(char *str1)
{
int i;
int x;
x = strlen(str1)-1;
for ( i = 0; i<=x; i++)
{
if(str1[i] == str1[x-i])
{
printf(" Your String is a Palindrome \n");
return 0;
}
else
{
printf(" Your String is not a Palindrome \n");
return 0;
}
}
}

Methinks that you are comparing the 1st and last letter and calling it a day by returning 0. I would increment i in the if statement: if(str1[i] == str1[x-i]). And you only need to increment i to range x/2.

I'd do a few things differently.

void pal(char *str1)
{

int i;
int x;
x = strlen(str1)-1;

for (i = 0; i<=x; i++)
{
if (str1[i] != str1[x-i])
{
printf(" Your String is a not a Palindrome \n");
return 0;
}
}

printf(" Your String is a Palindrome \n");
return 1;

}



/edit: Keep going.. you're on the right track.



This post was edited by Dmon_Hunter on Oct 25 2013 04:15am