What is the molar concentration of a sodium hydroxide solution with a pH of 11.30?
a. 1.0 x 10^-7
b. 2.5 x 10^-3
c. 5.0 x 10^-3
d. 2.0 x 10^-3
e. 2.0 x 10^-12

Once again, I already have the answer to the problem, I just need someone to explain to me how to do it.

Dont remember exactly but from what I remember :

1 - apply stochiometry up on this bitch
2- NaOH contains OH so your relation is pOH = -log[OH]
3 - you know that 14 = pH + pOH

must be 2x10^-3

Ph = -log [h]

Then use same formula from previous thread this time solving for oh

I believe ^ post works too

+1 ahahaha