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#1
Oct 13 2013 08:21pm
How do you solve if x is an exponent?

Ex: 1400 = 5 x 2^n
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#2
Oct 13 2013 08:23pm
could you use better notation?

^ for exponents and () to encase them
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#3
Oct 13 2013 08:30pm
tldr log

Quote (Hirokiy @ Oct 13 2013 10:21pm)
How do you solve if x is an exponent?

Ex: 1400 = 5 x 2^n


i assume 1400 = 5*(2^n)

1400 / 5 = 2^ n
log_2 (1400/5) = n
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#4
Oct 13 2013 08:30pm
Quote (Hirokiy @ 14 Oct 2013 02:21)
How do you solve if x is an exponent?
Ex: 1400 = 5 x 2^n


1400 = 5 x 2^n => 280 = 2^n => n=log2(280) .... ie log2= logarithm to base 2
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