I'm studying for an Analysis Exam and came across this review problem that has me stumped.

Suppose that s_n converges to pi. Prove that there is a real number N such that if n > N, then s_n < (22/7)

I know the definition of convergence (Given epsilon>0, there exists some N such that if n>N, |s_n - s| < epsilon), but I don't know how to apply it

Since 22/7 > pi, just choose an epsilon > 0 such that pi + epsilon < 22/7

There exist N such that for every n>N, |s_n - pi| < epsilon, and that implies s_n < 22/7.

/hint 22/7 = 3.142857... and pi = 3.14159... from one point on the elements of the series will all be closer to pi than to 22/7

are you sure it says "real number N"?

awesome, thx guys.
and yes, it says real number