1)
a)V_x=5.78*cos(Ѳ)
b.)V_y=-5.78*cos(90-Ѳ)
Vf = a*t + Vi
Vf = 5.78*cos(90-Ѳ) m/s
a= -9.8 m/s^2
Vi = 0
Ѳ=50
solve for t in seconds
Df = 1/2*a*t^2 + Vi*t + Di
Df = 0 m
a = -9.8 m/s^2
t = from above
Vi=0 m/s
c)Solve for Di in meters
Df = (1/2)*a*t^2 + Vi*t + Di
a = 0
t = from above
Vi = 5.78*cos(Ѳ) m/s
Di = 0 m
d)Solve for Df in meters
This post was edited by Azrad on Oct 10 2013 10:34pm