Quote (Zyed @ Oct 7 2013 10:24pm)
Next, what's an easy method to find a point on a line with not so nice x and y intercepts?
Example - y=2/3x-5/3
Set x equal to 0, then calculate what the resulting y value would be, and now you have a point on that line: {0,result of calculation using x=0}
or in your specific example:
(I'm assuming that dash in front of the y is not a negative sign.... )
y = (2/3)*0 - (5/3)
y = -5/3
{0,-5/3}
This post was edited by Azrad on Oct 8 2013 05:23am