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Oct 6 2013 10:15pm
I need help with this :

I have a transfert function and I want to know the numerical value of the output if the input is a square wave of 1Vpp , duty cycle of 50% and a frequency of 20KhZ

My guess would be to start with H(s) = Vout/Vin

Vout = Vin*H(s) and put s = (20k*2pi*i), but wut do with Vin? do I use Vrms=0.5 and thats it?

This post was edited by LeB on Oct 6 2013 10:19pm
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Oct 7 2013 07:25am
take the fourier series of the square wave and multiply the result with the transfer function
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Oct 7 2013 08:52am
Quote (hasuchObe @ Oct 7 2013 08:25am)
take the fourier series of the square wave and multiply the result with the transfer function


But that doesnt give me a numerical value , does it? Its still dependant on t as i have

f(t) = sum[ 4/pi[sin(2pi*n*t/T)] ]
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Oct 7 2013 09:36am
the fourier coefficients are given to you in the equation you just wrote. just multiply those with the corresponding frequencies and you're done. however, i take it that i might have to explain more but ill let u think about it first.
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Oct 7 2013 11:47am
Quote (LeB @ Oct 7 2013 09:52am)
But that doesnt give me a numerical value , does it? Its still dependant on t as i have

f(t) = sum[ 4/pi[sin(2pi*n*t/T)] ]


lol lebs dumb as fuk
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Oct 7 2013 04:53pm
Quote (AZ-Brothers @ Oct 7 2013 12:47pm)
lol lebs dumb as fuk


lmao wat a fagget

Quote (hasuchObe @ Oct 7 2013 10:36am)
the fourier coefficients are given to you in the equation you just wrote. just multiply those with the corresponding frequencies and you're done. however, i take it that i might have to explain more but ill let u think about it first.


I'm not exactly familiar with the behavior of the fourier series, i know that a given time it can either be -0.5V or 5V. My guess would be to take my vin as Vpp = 1v, but i'm not entirely sure. any tips?

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