d2jsp
Log InRegister
d2jsp Forums > Off-Topic > General Chat > Homework Help > Where Am I Messing Up?
Add Reply New Topic New Poll
Member
Posts: 23,281
Joined: Jul 23 2008
Gold: 10.00
Sep 27 2013 09:59pm


wouldn't it be
15 / 8 ---> 15y - 15 x = 8y
solving for y
y = 15/7

so would'nt it be
15/7 (8)

where am I going wrong
Member
Posts: 23,281
Joined: Jul 23 2008
Gold: 10.00
Sep 27 2013 10:02pm
wait or would I be solving for y which is 15y - 15x = 6y because of his height instead of the feet per second his walking?
Member
Posts: 35,671
Joined: Aug 11 2008
Gold: 2,130.00
Sep 28 2013 01:17am
dont u gotta set up 2 constant acceleration equations for X and Y directions and set it equal to eac other?
Member
Posts: 16,662
Joined: Nov 24 2007
Gold: 15,245.00
Trader: Trusted
Sep 28 2013 06:03am
First, notice that the answers doesn't depend on the position from the base (10 feet in your case).

Intercept theorem (Thales' theorem) proves that the length of the shadow equals 8/7 of the position from the base.
If the position from the base changes at a rate of 8 feet/sec, the length of the shadow changes at a rate of (8/7)*8 = 64/7 feet/sec.

The distance between the tip of the shadow and the base of the light equals the length of the shadow plus the distance between the man and the base of the light.
The velocity of the tip, hence, is the sum of the velocity of the man and the velocity of the length of the shadow :
8 feet/sec + 67/7 feet/sec = 120/7 feet/sec.
Member
Posts: 10,812
Joined: Oct 15 2009
Gold: Locked
Warn: 20%
Sep 28 2013 02:23pm
for part a
  • 1 Express the position of the tip of the shadow as a function of time
  • 2 Take the derivative of this function with respect to time
  • 3 Figure out how long the man was walking (get a value of time)
  • 4 substitute this into the derivative
1) P(t) is position of the tip of the shadow, also the length of the base of the big triangle
similar triangles:
(9)/(8t) = 15/[P(t)]
P(t) = (40*t)/3

2)dP/dt = 40/3 f/s
We can skip step 3 and 4 since time disappeared from our equation (preforming step 3 and 4 won't change our answer, since there is no t to replace).

This post was edited by Azrad on Sep 28 2013 02:36pm
Member
Posts: 10,812
Joined: Oct 15 2009
Gold: Locked
Warn: 20%
Sep 28 2013 02:53pm
for part b:


clearly:
dP/dt = da/dt + db/dt
We know dP/dt is a constant (40/3 f/s), and we know da/dt is a constant (8 m/s), therefore db/dt had also better be a constant so we can just use simple algebra for it:

40/3 = 8 + db/dt
db/dt = 16/3 f/s
Member
Posts: 16,662
Joined: Nov 24 2007
Gold: 15,245.00
Trader: Trusted
Sep 28 2013 03:10pm
Quote (feanur @ Sep 28 2013 01:03pm)
First, notice that the answers doesn't depend on the position from the base (10 feet in your case).

Intercept theorem (Thales' theorem) proves that the length of the shadow equals 8/7 of the position from the base.
If the position from the base changes at a rate of 8 feet/sec, the length of the shadow changes at a rate of (8/7)*8 = 64/7 feet/sec.

The distance between the tip of the shadow and the base of the light equals the length of the shadow plus the distance between the man and the base of the light.
The velocity of the tip, hence, is the sum of the velocity of the man and the velocity of the length of the shadow :
8 feet/sec + 67/7 feet/sec = 120/7 feet/sec.


I had a 8 feet heigth man in mind... sorry for this confusing post.

Azrad' explanations are correct.
Member
Posts: 10,812
Joined: Oct 15 2009
Gold: Locked
Warn: 20%
Sep 28 2013 03:17pm
Quote (feanur @ Sep 28 2013 02:10pm)
I had a 8 feet heigth man in mind... sorry for this confusing post.


heh yeah your description sounded good but i couldn't follow your work (and now we know why) :P
Also I couldn't see ahead that the solution was not a function of time---I would have guessed otherwise---but can't argue with the results.

This post was edited by Azrad on Sep 28 2013 03:22pm
Member
Posts: 23,281
Joined: Jul 23 2008
Gold: 10.00
Sep 28 2013 07:16pm
Yeah I got it! That was the mistake I made with the 8 feet being height haha
Thanks Azrad for the explanation
Go Back To Homework Help Topic List
Add Reply New Topic New Poll