3.) What is the average rate of change of f(t) = t^2 – 2t between t = 2 and t = 2+hCalculate the output of that function for the 2 different inputs provided. These 2 points define a line. The average rate of change is the slope of that line (use the old slope formula).
4.) Describe the transformations from f(x) = x^3 to g(x) = -(x-1)^3x^3 -> (x-1)^3 is shifting one to the right
(x-1)^3 -> -(x-1)^3 is reflection about the x axis
5.) What transformation occurs if f(x) becomes f(3x)shrink by factor of 3 (horizontal shrink)
6.) Translate f(x) = x^2 – 2x +3 left 2 units. Write in standard form.(x+2)^2 - 2(x+2) + 3, you can simply this on your own
7.) Horizontally stretch g(x) = 8x^2 – 4x + 6 by a factor of 2. Write in standard form.8(x*0.5)^2 - 4(x*0.5) + 6, you can simply this on your own
8.) Let h(x) = x^2 – 1, where x less then or equal to 0. 2x + 4, where x greater than 0.not a question, IMO
9.) Evaluate h(-2) and (1). (Use the problem 8)hesitant to answer since 8 is confusing
11.) f(x) = x^3 + 5, find the inverse function.solve for x, then switch the x and f(x) in the function
13.) f(x) = square root of x^2 -9 and g(x) = square root of g(x) = 25 – x^2. What is the domain of f + g?x>=3 or x<= -3(from the first equation), and x <=5 or x>=-5 (from the 2nd equation); i think you can do the rest
14.) On which intervals is f(x) = 3x^4 – 10x^2 + 5x – 3 increasing?heh not actually sure how to get this answer without calculus, which of course would not help you
15.) A isosceles triangle has a perimeter of 12 units and a base of b. Write a function for the area of the t in terms of base b. ( I think I got this one just want to be sure)if we bisect the triangle it will give us 2 identical right triangles. The base of one of these triangles will be (1/2)b, one of the sides will be unknown, and the hypotenuse will be (1/2)*(12-b). Now you have 2 sides of a right triangle expressed (using b). Pythagoras theorem will give you the unknown side (which is also the height of the original triangle) in terms of b. Now you have the base of the original triangle in terms of b (it is b), and the height in terms of b (from Pythagoras theorem), so you can get calculate the area as these 2 numbers multiplied together * 0.5 using the old school (1/2)* base* height idea.
This post was edited by Azrad on Sep 19 2013 06:36pm