1.
Figure/graph, shows the velocity graph of a particle moving along the x-axis. Its initial position is X_0= 2.0 m, at t_0 = 0s. At t=2.os, what are the particles (a)position, (b) velocity, (c) acceleration.
The graph is just a steady incline of 2 meters per second (ie: up2 over 1) or y=2x

2.
A particles velocity is described by the function
V_x=t^2-7t+10m/s where t is in seconds

a. At what time does the particle reach its turning point
b.What is the particles acceleration at each of the turning points?

3.
A car accelerates at 2.0 m/s^2 along a straight road. It passes two marks that are 30m apart at times t=4.0s and t=5.0s. What is the cars velocity at t= 0s

Could use formulas and how to plug the equations in etc.

a) position is just the dependent variable. In your case I believe it is 4
b.) the velocity is the rate of change of position, or the slope of the line, which you said is 2
c) the acceleration is the rate of change of the velocity (or the rate of change of the slope, which should be 0 if it is a line).

This post was edited by Azrad on Sep 11 2013 08:58pm

Hmm doubt its that easy all of the problems in my book are complicated /=

doesn't X_0=2m at t_0=0s mean as 0s your at 2m?

at time=0, you're at x=2m

soo if im moving 2m/s, after 2 seconds im at 6m right?

then i have to calculate my velocity at 2 seconds and acceleration

which my velocity is constant soo it should be 2? and acceleration 0?

I have 1 done need 2 and 3 still

2set V(x) = 0 and solve for t
plug in the values of t from above into dV/dt

This post was edited by Azrad on Sep 11 2013 10:02pm

3

Pf = (1/2)*a*t^2 + Vi*t+Pi
Pf = 30m
Pi = 0m
a = 2.0 m/s^2
t = 1 s
solve for Vi... now you know the velocity at t=4
--------------------
Vf = a*t + Vi
Vf = velocity at t = 4
a = 2.0 m/s^2
t= 4 seconds
Vi = velocity at t=0

This post was edited by Azrad on Sep 11 2013 10:09pm

No
"Figure/graph, shows the velocity graph of a particle" + "The graph is just a steady incline of 2 meters per second (ie: up2 over 1) or y=2x"

I'm pretty sure you meant "y=2t", velocity changing with time and not with x, otherwise this will probably go into differential equ



position will be , position_x= t^2 + 2
accel is derivative of velocity, so take the derivative of v=2t, and accel=2