When x + 2 is divided into f(x) the remainder is 3. Determine the remainder when x + 2 is divided into f(x) + 1.

Either 0 or 4 i assume? You have one extra slot open, so either your remainder increases by 1 or it's evenly divisible.

4 mod (x + 2) would be my answer

This post was edited by carteblanche on Sep 10 2013 07:17pm

when you say x divided into y is that
x/y
or
y/x

f(x) / ( x + 2 )

Are you allowed to assume the remainder theorem?

Given f(x) / (x+2) = Z*(x+2) + 3 where Z stands for an integer
multiple (x+2) on both sides to get: f(x) = Z*(x+2)^2 + 3*(x+2)

So we know f(x) is a polynomial of form Ax^2 + Bx + C

At this point you can just refer to example 2 of http://en.wikipedia.org/wiki/Polynomial_remainder_theorem
for the proof of remainder theorem if you aren't allowed to just assume it.

Using that theorem, we know that f(-2) = 3
Let G(x) = f(x)+1
Then the remainder of (f(x)+1)/(x+2) is the remainder of G(x)/(x+2) which by the remainder theorem is G(-2)
G(-2) = f(-2) + 1 = 3 + 1 = 4

the answer is 4

tyvm for explaining really well