Starting my last year of highschool after summer but need to finish an old math course before summer.

Only thing I forgot is how to solve with different bases.

example: 231 (base 5) = ? (base 10)


a) Convert: 237(base3) * 34 (base 6) / 21 = ? (answer in base 4)

b ) 73(base 10) = 201 (b) <-- What base is b?

This post was edited by mavajava on Jun 9 2013 05:19am

237(base 3) does not exist, with base 3 only 0,1,2 are used (could it be base 8?)

73(base 10) is 73, now need to solve the equation 2a^2+0a+1 = 73 ie 72 = 2a^2 ie 36 = a^2 ie .... 73(base 10) = 201 (base 6)

the principle is: abcdefghi(base x)= ix^0 + hx^1 + gx^2 + fx^3 + ex^4 + dx^5 + cx^6 + bx^7 +ax^8 and same principle for 'longer' numbers

This post was edited by brmv on Jun 9 2013 05:32am