i feel so stupid its part of a derivation for my class i can simplify it to this

wolfram gets it to 2^z so i know its right anyways iso step by step help

(x/y^z-x/(2^z y^z))/(x/(2^z y^z)-x/(4^z y^z))

can you write it on multiple lines so it's more readable?

first multiply the first term with 2^z/2^z and the third term also with 2^z/2^z

(x 2^z/(2^z y^z) - x/(2^z y^z) / (x 2^z/(2^z 2^z y^z) - x / (4^z y^z))

now combine the first two terms and the third with the fourth taking note that 2^z 2^z = 4^z

((x 2^z - x) / (2^z y^z)) / ((x 2^z - x) / (4^z y^z))

now switch the division of the second to make it a multiplication

((x 2^z - x) / (2^z y^z)) * ((4^z y^z) / (x 2^z - x)

now you can eliminate the (x 2^z - x) and switch the terms

(4^z y^z) / 2^z y^z)

now eliminate y^z

4^z / 2^z and with 4^z = 2^z 2^z you divide by 2^z and have your result