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#1
Apr 29 2013 11:04pm
http://i1209.photobucket.com/albums/cc393/ChickenxChaser/Calc2_zpsda83aa58.png
Thanks!

This post was edited by ChickenxChaser on Apr 29 2013 11:05pm
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#2
Apr 30 2013 01:03am
implicit differentiation

1y^3 + x*3*y^2*y' + 1y+x*y' = 0
3xy^2y' +xy' = -y^3 - y
y'(3xy^2 + x) = -y^3 - y
y' = (-y^3 - y)/(3xy^2 + x)

This post was edited by Azrad on Apr 30 2013 01:05am
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