Now using the version of the function I wrote above:
Quote (snowy1109 @ Apr 9 2013 03:36pm)
1) the outside temperature is -20 degrees Celsius how much food energy is required per day?
E(-20)=-125*(-20-122) = 17750 kj
Quote (snowy1109 @ Apr 9 2013 03:36pm)
2)If a hiker consumes 19000 kj of food energy based on the outside temperature what is the temperature
E(t)=-125*(t-122)=19000
t-122=19000/-125
t=(19000/-125) + 122
t = -30 c
This post was edited by Azrad on Apr 9 2013 05:17pm