LOLOLOLOLOLOOLOLLOLOLOLOLOLOLOOL

.99999 =/= 1 because they are not the same number

you can minupulate proofs to make it look that wat but i have also seen a proof that states 1 = 2, so unless you want to argue that 1 = 2 then .9999 =/= 1 it will always be .<infinite 0's>1 away from 1, you can however say its essentially one, seeing as how .<infinite 0's>1 is so insignificant

show me this proof of 1=2 because thats just silly

what about bumps?

I've made one of these.

LET X = Y = 1

x^2 - x^2 = 0
x^2 - y^2 = 0 (Substitute Y in for X)
(x+y)(x-y) = 0 (Difference of squares)
(x+y) = 0 (Divide by (x-y))
x = -y
1 = -1

If you'll notice, proofs like the one I just put here, and the one you saw that states 1=2, have some internal error in them. In this proof I divided by 0 (x-y).

EDIT: There have been many proofs already posted on this thread about how .9999... = 1 so I won't add more of them, but if you don't believe that .99999... = 1:
http://mathforum.org/library/drmath/view/57035.html
Dr. Ethan has a doctorate in mathematics, his word has weight to it.

EDIT 2:



Is 0.00....1 a number? No.

This post was edited by Snakesrcool on Jun 9 2010 07:36pm

and you kept this on for 82 pages?

one stupid question for mankind and one giant leap for trolls.

You can express it in a mathematical way. So it should be a number.

0.999... / 9 * 9 = 0.111... * 9 = 1/9 * 9 = 1

/thread

It's not a real number. Infinitesimals are not real numbers.