d2jsp
Log InRegister
d2jsp Forums > Off-Topic > General Chat > Homework Help > Does .999999... = 1? > Iso Proofs
Prev17879808182121Next
Closed New Topic New Poll
Member
Posts: 3,053
Joined: Apr 8 2010
Gold: 0.00
Warn: 50%
Jun 3 2010 04:59pm
Quote (hotdogski @ Apr 11 2010 08:10am)
lol...

When you divide by 1 by 3 you get an infinite number

http://www.google.com/search?q=1%2F3&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a

now put that same number on your calculator and multiply by 3.

What do you get?

If you multiply an infinite number by the reciprocal of its divisor, then of course you are going to get what you started with... but just go ahead and try to multiply that infinite number, your argument its moot. And not even worth arguing..


lold
Member
Posts: 3,053
Joined: Apr 8 2010
Gold: 0.00
Warn: 50%
Jun 3 2010 04:59pm
Holu fucking shit that's alot of replies.
But i agree with the lold^
Member
Posts: 430
Joined: Jun 19 2008
Gold: 111.10
Jun 3 2010 05:14pm
Quote (murder567 @ Jun 3 2010 06:59pm)
how retarded are u? lol
subtract this from one side and something different from the other
u have to do the SAME thing to each side
like i cant say

3x = 1
then add 4x to 1 side and subtrac 3 from another
7x = -2

x has 2 diff valus in there because u did different thing from each side. your a fucking tard


what

x has one value. he never did different things to both sides (he did use 'x' and '0.999...' interchangeably, which is fine since they are equal).

please point to the specific steps in which you believe he did different things to each side. oh, look at that...
Member
Posts: 18,180
Joined: Jun 5 2009
Gold: 5.00
Warn: 10%
Jun 4 2010 06:33am
Quote (Scorch1272 @ Jun 1 2010 09:15am)
This thread should not have carried on this long... it runs along the lines of the concept of infinity in that 1 / 3 (for example) is an absolute number... but when converted to its decimal form there is an infinite number of decimal places, and this number no longer is exact, therefore 3 * .333333333.... = 1 is inaccurate due to the inability to have infinite decimal places


The term 0.333... means infinitely recurring, so it IS possible to have infinite decimal places.

Quote (red_man_27 @ Jun 1 2010 05:31am)
lol your arguments are dumb.
we all know 0.9999999999 does not equal 1
a preschool kid could tell you that.


I'm sure a preschool kid would tell me that.
But a mathematician would tell me otherwise.
Member
Posts: 212
Joined: Feb 5 2010
Gold: 336.50
Jun 5 2010 05:41pm
Quote (Hammer_Hdin @ Jun 4 2010 06:33am)
The term 0.333... means infinitely recurring, so it IS possible to have infinite decimal places.



I'm sure a preschool kid would tell me that.
But a mathematician would tell me otherwise.


x=.9999999999999

If i have 10x = 9.9999999999

Subtract x from ea side (.999999999 from the side without x)

Divide ea side by 9

x=1


(-x) 10x = 9.9999999999 (-.999999999999)
(/9) 9x = 9 (/9)
x = 1


10x = 9.9999999999
9x = 9
x = 1
Member
Posts: 9,039
Joined: Nov 16 2009
Gold: 581.50
Warn: 10%
Jun 5 2010 05:55pm
If I post a pornographic picture here, will I just get a warn/temp ban, or is there a chance that this thread will actually get closed?
Member
Posts: 10,365
Joined: Aug 5 2007
Gold: 0.00
Jun 5 2010 07:44pm
let Q be the field of rational numbers
let t be .999 repeating
let Q(t)/Q be the field extension of Q by adjoining t
Then Q(t) = {a + bt | a,b belong to Q}
take x in Q(t)
x = m + nt
t = .9 repeating
10t = 9.9 repeating = 9 + t
x = m + (10t-9)t = m + 10t^2 -9t belongs to Q(t) = {a + bt | a,b belong to Q}
hence 10t^2 belongs to Q(t) ==> t^2 belongs to Q(t)
then either
or t^2 is in tQ ==> t is in Q ==> Q(t) = Q
t^2 is in Q ==>[Q(t):Q]=2
t^2 = .99.^.99. = .9*.9 + 2*.099.*.9 + .09.*.09. = .81 + .179.+.0081 = .99. = t ==> t belongs to Q ==> Q(t) = Q
either way Q(t) = Q

hence I've shown that t is in Q
then t = a/b | a,b belong to N the natural numbers
a = bt
10a = 10bt = 9b +bt = 10a
10a - bt = 9a = 9b ==> a=b ==> t = a/b = 1/1 = 1
Member
Posts: 12,566
Joined: Sep 15 2009
Gold: 0.00
Jun 6 2010 04:36am
Bump
Member
Posts: 10,633
Joined: Sep 15 2007
Gold: 0.00
Jun 6 2010 05:20am
Quote (soulofdragon @ Jun 6 2010 09:41am)
x=.9999999999999

If i have 10x = 9.9999999999

Subtract x from ea side (.999999999 from the side without x)

Divide ea side by 9

x=1


(-x) 10x = 9.9999999999 (-.999999999999)
(/9) 9x = 9 (/9)
x = 1


10x = 9.9999999999
9x = 9
x = 1


MMMMMMMMM DELICIOUS COPYPASTA CAN I HAVE MOAR OF THIS DELIGHTFUL PROOFZ?!?!
Member
Posts: 5,030
Joined: Jun 11 2009
Gold: 817.00
Jun 7 2010 12:26am
+1 for 800 posts in this topic
Go Back To Homework Help Topic List
Prev17879808182121Next
Closed New Topic New Poll