No, not quite. That's not what I implied.

If you establish a pattern (as you did when you said '1, 2'), then the ellipse implies that this continues on forever, unless you specify an endpoint (as you did when you said ', n').
So 1, 2, ..., n means all positive integers up to and including n. What you said ("infinite numbers between 1 and n") doesn't agree with the pattern you established. You're clearly dealing with integers, and there are not infinite integers between 1 and n, no matter what n is (of course assuming n is a real number, but that doesn't really matter anyway).

There's a big difference between "1, 2, ..., n" and 0.000...1. The most important difference is that the former indicates a set, while the latter is a number.

edit: fail troll is fail lols

This post was edited by chone on May 20 2010 06:56pm

and if i write 0.000...1 that means an infinite number of zeros?

more like if i write 0.000...1 , I cross/erase it because its wrong

edit : +60

This post was edited by Taxidermy on May 20 2010 08:22pm

0.0

I have the answer right here:

Sum of an infinite geometric series.

a/(1-r) where a = the first number of the series and r = the common ratio

0.9999 repeating can be seen as a geometric series like so: 9/10 + 9/100 + 9/1000 + 9/10000 ... etc

a/(1-r) turns into (9/10)/(1-1/10), or 9/9.

One of the simplest mathematical proofs is that anything divided by itself equals 1, so 9/9 = 1, and if 0.9 repeating equals 9/9, then it also equals 1.

i posted that on like page 2

wow stop with the spam...

lol

+0.999...

i posted that on page 40 or so

edit : +61

This post was edited by Taxidermy on May 20 2010 10:35pm

I don't understand what you're asking. No, there's not an infinite number of zeros. 0.000...1 just straight up isn't a real number. You can't have "an infinite number of zeros" with a 1 *after* it.

All of the proofs "converge" to 1, but do not equal 1.

Does not equal.

/thread

get out of here