refer to page 2 of this thread and see who posted that first

edit : +16

This post was edited by Taxidermy on May 6 2010 10:44am

It's pretty amazing that you're most likely clueless with regards to the mathematical proof but are still willing to accept it as fact.




http://forums.d2jsp.org/topic.php?t=41961785&p=287020420

This post was edited by Phils_Porsche on May 6 2010 10:57am

That's different math you just linked, that assumes x=1. That one's a bit backward.

I'm not really up on my higher maths, but what I posted is pretty much basic algebra and makes no such assumptions. A number multiplied by ten means you smack the decimal over to the right one spot. Pretty simple stuff.

bgfbgf

This post was edited by Phils_Porsche on May 6 2010 11:09am

zzz using logic is obviously retarded





(feel free to quote that one)

edit : +17

This post was edited by Taxidermy on May 6 2010 11:10am

huh

I hadn't thought of it this way and may have to revise my worldview based on this information.

Let x be 0.999...
10x=9.999...
10x-x=9.999... - 0.999...
9x=9
x=1

9x -x = 8x = 9- .999999..... = 8.0000.....001 = 8( .999999....)

Is that what you're also going to tell me? You're trying to prove .999.... = 1, you can't assume it from the very beginning.

That "proof" isn't rigorous at all. I thought you were good with this logic stuff?

This post was edited by Phils_Porsche on May 6 2010 03:20pm

so you guys think that

9.999.... -0.999 =9.0000.....1
i.e. 9 with some infinitely small leftover part?

pathetic....

edit : +18

This post was edited by Taxidermy on May 6 2010 03:53pm

As I mentioned earlier - there's no such thing as ... and then a number, as far as I know. Saying "After infinity, put this digit" is utterly meaningless.

I didn't say it was particularly rigorous, I just said it was correct and I had yet to see anyone poke a hole in it. If someone can poke a hole in it, then we can go with something with more rigor.

a number that infinitely approaches another, for all intensive purposes is usually called the second number
but technically no it's not :/