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Apr 20 2013 01:52pm
for 3c, the voltage goin through the capacitor will be 12 volts right? therefore the charge will be q = CV
q = (2)(12)
q = 24
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Apr 20 2013 02:23pm
Quote (FamilyGuyViewer @ Apr 20 2013 02:52pm)
for 3c, the voltage goin through the capacitor will be 12 volts right? therefore the charge will be q = CV
q = (2)(12)
q = 24


that's correct(remember its going to be rated in uC not C), not sure exactly how to word the answer for 1A

This post was edited by drxscillator on Apr 20 2013 02:24pm
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Apr 20 2013 04:36pm
Quote (FamilyGuyViewer @ Apr 20 2013 01:14pm)
how do i explaint he first part using ohms law..


Use KCL and current divider knowledge.
http://en.wikipedia.org/wiki/Kirchhoffs_Current_Law
http://en.wikipedia.org/wiki/Current_divider

This post was edited by DynastyFury on Apr 20 2013 04:37pm
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Apr 20 2013 07:19pm
Quote (drxscillator @ Apr 20 2013 04:23pm)
that's correct(remember its going to be rated in uC not C), not sure exactly how to word the answer for 1A


oh ok , so wats the unit for charge than? and uF is 10^-6? fareds?
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Apr 20 2013 07:28pm
Quote (FamilyGuyViewer @ Apr 20 2013 08:19pm)
oh ok , so wats the unit for charge than? and uF is 10^-6? fareds?


Charge is rated in coulombs. yeah uF is microfarads (10^-6)
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Apr 20 2013 07:55pm
Quote (drxscillator @ Apr 20 2013 09:28pm)
Charge is rated in coulombs. yeah uF is microfarads (10^-6)


so..
q = CV
q = (2x10^-6F)(12V)

q = 24x10^-6 coulumbs?

fareds time voltage = coulombs?
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Apr 20 2013 08:09pm
Quote (FamilyGuyViewer @ Apr 20 2013 08:55pm)
so..
q = CV
q = (2x10^-6F)(12V)

q = 24x10^-6 coulumbs?

fareds time voltage = coulombs?


right

1 F = 1 C²/J
1 Volt = 1 J/C

J/C * C²/J = C

This post was edited by drxscillator on Apr 20 2013 08:11pm
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Apr 20 2013 10:39pm
Quote (drxscillator @ Apr 20 2013 10:09pm)
right

1 F = 1 C²/J
1 Volt = 1 J/C

J/C * C²/J = C


ah ok sigh im getting a diff answer for 1e, saying it wont effect cuz their parallel just wat I was thinking at first
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