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Apr 29 2010 05:30pm
Quote (sevlo @ Apr 29 2010 11:13pm)
Pfft.
0/0 can be equal to any constant.

http://i44.tinypic.com/2j4d3sj.jpg

My methods are purely mathematical. Yours is not, you didn't even prove anything (learn induction maybe?). Reconsider who is the retard.

Nvm.


that's why they say that 0/0 is undefined. which means you can't actually say it equals 1.
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Apr 30 2010 01:30am
Quote (sevlo @ Apr 30 2010 12:18am)
At least apologize...


hahahaah you got that from me! xD
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Apr 30 2010 02:44am
Quote (Viona @ 30 Apr 2010 02:30)
that's why they say that 0/0 is undefined. which means you can't actually say it equals 1.


It can be equal to any constant. It's undefined on its own, but if the original fraction is similar to mine above, 0/0 could be equal to any real number. It's just the uninformative form of the number (such as denoting it with a letter, say, c).

The value of 0/0 depends on the situation, so to say.

This post was edited by sevlo on Apr 30 2010 02:45am
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Apr 30 2010 03:13am
Quote (thefarmstudio @ Apr 27 2010 08:55pm)
Oh, you are so wrong. Now don't take it personally please :)

0.99999 does not equal 1

0.9(9) also does not equal 1
Proof: 0.9(9) means that the number 9 keeps repeating itself, right? Like 0.9999999999.... and so on. But no matter how many 9's there are, the number will never reach 1. Like if you keep dividing the same number by two, it will never ever ever reach 0, no matter how small the number becomes. Same is here - no matter how close the number 0.9999(9) is to 1, it will never equal one.

EDIT: Now, if you include limitsto the whole picture things will start making more sense.
http://en.wikipedia.org/wiki/Limit_%28mathematics%29


You're wrong.
And do you know why?
Because infinity is not a proper number.
For example, infinity + 999999 = infinity
infinity - 999999 still equals infinity.
Once something is infinite, the rules of the number change slightly.
For example, 0.999 X 10 = 9.99 and then if you take away 0.999 you get 8.991
Whereas, if you do 0.999 (infinitely recurring) X 10 you will get 9.9999 (infinitely recurring).
If you do 9.9999 (infinitely recurring) take away 0.9999 (infinitely recurring) then you will get 9, which divided by 9 = 1
The rules work slightly differently with an infinite number because you can add and subtract things from infinity and it will still be infinity, whilst if you add and subtract things from a real number then it will change the whole number.
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Apr 30 2010 06:01am
Lol I love how this has reached 30 pages.
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Apr 30 2010 06:08am
Quote (CPK001 @ Apr 30 2010 02:01pm)
Lol I love how this has reached 30 pages.


and how some math experts (like darkfire) have explained it all perfectly, and still some people think that 0.9(9) does not equal 1 ^^
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Apr 30 2010 06:10am
Quote (Viona @ Apr 30 2010 10:08pm)
and how some math experts (like darkfire) have explained it all perfectly, and still some people think that 0.9(9) does not equal 1 ^^


Power of algebra helped me through that.

10x - x = 9x etc.

I don't see any flaws to make that logic invalid.
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Apr 30 2010 07:22am
Quote (CPK001 @ 30 Apr 2010 15:10)
Power of algebra helped me through that.

10x - x = 9x etc.

I don't see any flaws to make that logic invalid.


Thank you.
No crediting for my 0,00000...1 = 0 proof :D ?

This post was edited by sevlo on Apr 30 2010 07:23am
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May 1 2010 04:54am
One divided by three is equal to 1/3 or 0.333 repeater

1/3 multiplied by 3 is equal to 1

0.333 repeater multiplied by 3 is equal to 0.999 repeater

Hence 1 is equal to 0.999 repeater
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May 1 2010 04:59am
Quote (sydney @ May 1 2010 06:54am)
One divided by three is equal to 1/3  or 0.333 repeater

1/3 multiplied by 3 is equal to 1

0.333 repeater multiplied by 3 is equal to 0.999 repeater

Hence 1 is equal to 0.999 repeater


Meh it's easier to do with 9'ths (1/9 = .111111111111 etc. and 9/9 = 1, so .1111111 * 9 = 1.) makes things simple for people who can't multiply 3's
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