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#221
Apr 25 2010 10:42am
Quote (Forg0tten @ Apr 25 2010 03:47am)
Will always reach out to 1, will never ever reach the number itself.

/e Whoever posted that wikipedia ''x = .999'' stuff, there's an obvious flaw.
10x - x = 9.999 - .999
You're then getting rid of the .999 on the right side
How in heavens name do you get 9x???

10x - x = 9.999 - .999
+x
10x = 9.999
You're back at the beginning. gratz


ok watch this ... forget what x is...

what is 10x - x? its 9x

this is for ANY x.

gg no re
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#222
Apr 25 2010 05:12pm
Quote (rchau @ Apr 25 2010 10:08am)
there's this thing in calculus called limits breh...


Limits are what a function approaches regardless of what the function equals. Take this function. x^2 for any real number =/0. At x=0 it takes on the function x-1000.
What's the limit as x->0? Well 0 ofc. What's the value at x=0? -1000..
Therefore argument invalid.
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#223
Apr 25 2010 07:18pm
Quote (Thann @ Apr 25 2010 04:12pm)
Limits are what a function approaches regardless of what the function equals. Take this function. x^2 for any real number =/0. At x=0 it takes on the function x-1000.
What's the limit as x->0? Well 0 ofc. What's the value at x=0? -1000..
Therefore argument invalid.


You must be trolling us.
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#224
Apr 26 2010 02:34am
Quote (fastblink @ 24 Apr 2010 23:56)
WHY THE FUCK IS THIS THREAD STILL ALIVE. IT DOES EQUAL 1, you retards.

1/3 = .333333
2/3 = .666666

u add them u get

3/3 = .999999

THE END !


Who's the retard?

I study philology, and it's pointless to say I'm obviously not quite good at Maths, but at least I know some basics. You're summing up infinite numbers (or whatever you call them in English, I'm Spanish).

From my "ihavenoclue" point of view, and provided you're example:

1000/3 = 333
Then 333 x 3 = 1000 LOL obvious. FUCK NO.

You're simplifying the numbers you sum up, and so I did.

This post was edited by JiMbOAbSoLuT on Apr 26 2010 02:37am
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#225
Apr 26 2010 06:37am


LOL
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#226
Apr 26 2010 06:40am
Quote (JiMbOAbSoLuT @ Apr 26 2010 02:37pm)
http://www.youtube.com/watch?v=JOl6Pd5RwQY

LOL


this is actually correct.
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#227
Apr 26 2010 07:22am
Quote (Viona @ 26 Apr 2010 13:40)
this is actually correct.


The poster above is actually correct.
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#228
Apr 26 2010 09:55am
Quote (JiMbOAbSoLuT @ Apr 26 2010 03:34am)
I'm obviously not quite good at Maths.


This is the only correct statement in your post...
and get that green shit out of your messages

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#229
Apr 26 2010 10:33am
And now...

under modulo addition in the klein-4 group...

2+2 != 4
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#230
Apr 26 2010 10:58am
Quote (Thursdayisgod @ Apr 26 2010 11:33am)
And now...

under modulo addition in the klein-4 group...

2+2  != 4


What exactly is "2" in V? Since V is isomorphic to C_2 x C_2, we might take the interpretation of "2"as 2x2, in which case we have we have "2" = 2x2 = 4x4 = 0x0 and so 2x2 + 2x2 = 0x0 = 4x4 = "4".
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