right! and what about in 2.6

Not sure what you're asking about it.

A square root is the same thing as a 0.5 exponent, so I rewrote the square root as an exponent to get 15 * x^0.5 - 12x^.5

At this point it is a derivative just like all the others. The 15 and 12 remain because they are not "plain numbers" they are part of the terms containing the variable x.

Multiply 15 by the exponent (0.5), subtract one from the exponent (0.5 - 1 = -.5) and you get 7.5x^-.5, and do the exact same for -12x^0.5

Okay so the square root is an o.5 exponent everytime?

Yes.

o.O I didn't even know that :D

Yep, and a cube root is the same as 1/3, a fourth root is the same as 1/4, etc.

Okay I think i just have one more question. Could you explain how to do the chain rule?

Chain Rule:

(A + B)^C

The Derivative is:

(C - 1) * (A + B.) ^ (C-1) * The derivative of (A + B.)

So if your function is (5x + 3)^2

(2 - 1) * (5x + 3)^1 * (5) 5 Being the derivative of (5x + 3)


Looking at 2.7:

4(3X - 5)^2 - 1

(2 - 1) * 4*(3x-5)^(2-1) * (3) 3 Being the derivative of (3x-5). The -1 disappears because it is just a number not connected to a variable.

This post was edited by RzChaos on Nov 13 2015 08:03pm

fixed

Hehe thanks.