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Oct 27 2015 06:53am
Quote (Trig @ Oct 26 2015 10:01pm)
you guys have all been very very helpful! thank you so much. and if anyone wants the fg for helping just let me know, or I got a few more problems i wouldnt mind a sharp eye looking over and can send fg your way aswell!


http://i.imgur.com/VQsUDIn.png

here is my work:

A) 1360 / 4000 = .34
The percentage of orders from catalog users is 34% of total orders.

B ) 1826 + 33 / 4000 = .465
The percentage of orders from email or are major purchases are about 46.5% of total orders

C) The events are dependent. (this was a guess, wasn't sure how to determine on this one)

I understand the concept of dependent and independent but not sure how to determine with more complex examples as opposed to A B C > A pulled out w/o replacement > B C are left to pick.



You're correct on all of these, although it may not match the book answer correctly because they screwed up the math in their data table somewhere....major column adds up to 46 and not 56 like this table has...not sure how that is going to affect their answer. For dependent vs independent just look at percentages of each, and percentage of them both combined as the previous two people explained.
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Oct 29 2015 06:53am


These are the last two questions on the assignment I am struggling with...

for 6 would it be 1 - p( X <= 21)
so 1 - .864?

I have no clue for 6.
I do have something in my notes about for binomials that the
N = population size
p = prob

that the sample size has to be small compared to N

so if n = 300
sample size has to be N =< .05N

Does this come into play on #6 or no?
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Oct 29 2015 10:05am
For 6 it would be the probability of having 21 or fewer successes (already given) plus the probability of having exactly 22 successes. Just use the negative binomial/Pascal distribution formula, that's what they are looking for.

7 is exactly the same thing, with p=0.85 and n=200

This post was edited by russian on Oct 29 2015 10:07am
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