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Oct 27 2014 08:33am
Quote (ROM @ Oct 27 2014 09:01am)
Is the answer

x-y
-----
x+y

?

If yes, then I understand.



Actually could break that down further to just x-y?
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Oct 27 2014 11:24am
If I understood correctly:

√x-√y
-------- =
√x+√y

(√x-√y) . (√x-√y)
-------------------- =
(√x+√y) . (√x-√y)

(√x)² - 2(√x)(√y) + (√y)²
----------------------------- =
(√x)² - (√y)²

x - 2√xy + y
--------------- =
x - y

x + y - 2√xy
---------------
x - y

You will have to check domain:
√x+√y > 0
x - y ≠ 0

So, the values of x and y must be in this domain:
x > 0 and y >= 0

I hope I could help.

This post was edited by betoggc on Oct 27 2014 11:29am
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Oct 27 2014 10:29pm
Quote (betoggc @ Oct 27 2014 11:24am)
If I understood correctly:

√x-√y     
-------- =
√x+√y   

(√x-√y) . (√x-√y)   
-------------------- =
(√x+√y) . (√x-√y)   

(√x)² - 2(√x)(√y) + (√y)²   
----------------------------- =
        (√x)²  - (√y)²               

x - 2√xy + y   
--------------- =
  x - y             

x + y - 2√xy
---------------
  x - y

You will have to check domain:
√x+√y > 0
x - y ≠ 0

So, the values of x and y must be in this domain:
x > 0 and y >= 0

I hope I could help.


Hey, You want to be my friend?
Member
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Oct 29 2014 08:15am
lol. yes why not o_O
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