Quote (saber_x3 @ Sep 24 2014 08:51pm)

Area of bearing information is given to you
I don't think you understand the geometry of the set up if you have any questions on that.
It's literally like a wooden beam with 2 flat supports on both ends.

If you say those are 2 different types of loads then ok
that makes sense, since the deflection formula given to you is for distributed load

Quote (saber_x3 @ Sep 24 2014 09:45pm)

your problem clearly gives you a max bearing pressure

Quote (TheDiablo3KnowItAll @ Sep 25 2014 06:06pm)

how do I get the equivalent load for the 50lbft^2? is it 50*16*1.5?

Quote (saber_x3 @ Sep 25 2014 10:53pm)

It is a force per area.
(force per area)*(area)

You need to be careful about using 16 ft.
16 ft from center of bearing to center of bearing.
You have been given bearing dimensions.

Quote (saber_x3 @ Sep 26 2014 12:53am)

I don't understand how you'd think it's horizontal, into the screen.
The center of bearing to center fo bearing is 16 ft; the length of the beam is longer than 16ft..