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Feb 9 2014 09:45pm
Quote (Azrad @ 10 Feb 2014 02:40)
yes the only way a polynomial function  can have complex roots is if they come in conjugate pairs (like a+i*b, and a-i*b).
A first order polynomial function will have 1 real root.
A 2nd order polynomial function will have 2 complex or 2 real roots.
A 3rd order polynomial function will either have 4 complex, 2 real + 2 complex, or 4 real roots.
A 4th order polynomial function will either have 4 complex + 1 real, 2 complex + 3 real, or 5 real roots.


:rolleyes:

trolling? or tired?

total number of roots of any polynomial of degree n is n (counting multiplicities)
any polynomial of degree n with real coefficients and n being odd has at least one real root

probably tired i guess
seems you switched from 3rd order to 4th order in the middle of the line

This post was edited by brmv on Feb 9 2014 09:59pm
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Feb 9 2014 10:58pm
Quote (brmv @ Feb 9 2014 08:45pm)
:rolleyes:

trolling? or tired?

total number of roots of any polynomial of degree n is n (counting multiplicities)
any polynomial of degree n with real coefficients and n being odd has at least one real root

probably tired i guess
seems you switched from 3rd order to 4th order in the middle of the line


oh yeah i got messed up somewhere now that read back over it, they don't add up :)

anyway to the OP, complex one's always come in conjugate pairs, just remember that and you can deduce the possibilities yourself..
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