Quote (fingerling @ Jan 21 2014 09:53pm)
the domain of G(x)= 2/ [x^2 + x - 12]
fixed^^^
To restate what the other posters have said:
The domain is every possible value x can have that won't make that function "blow up in your face".
The only way for something to go wrong with that function would be if you evaulated (plugged in a value for x) the denominator and got 0
So the domain is
all real numbers except where:
x^2 + x - 12 = 0
So you need to solve that for, and it will give you value(s) for x that will make the function blow up in your face.
You can use many methods to solve it, but I will factor it:
x^2 + x - 12 = 0
(x+4)*(x-3) = 0
x = -4, x = 3
So the domain of x is all real values
EXCEPT x = -4 and x = 3