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Dec 1 2013 05:00pm
A = (0,80)
B = (1,125)
/e for post #8

A = (0,-1)
B = (1,2)
for #9

hypothenuse = 12
leg = 3
for #10

This post was edited by HbSoe on Dec 1 2013 05:04pm
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Dec 1 2013 05:15pm
Quote (HbSoe @ Dec 1 2013 11:00pm)
A = (0,80)
B = (1,125)
/e for post #8

A = (0,-1)
B = (1,2)
for #9

hypothenuse = 12
leg = 3
for #10



For answer A I need a pair that I can graph pref 1 to 10 is that possible?
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Dec 1 2013 05:23pm
(2,180)
#8

(3,2)
#9

is that what you need?
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Dec 1 2013 05:25pm
Quote (HbSoe @ Dec 1 2013 11:23pm)
(2,180)
#8

(3,2)
#9

is that what you need?


I need # 8 to be smaller # 9 is fine but the 180 is way out there lol im not sure if thats even possible though and I have one last question I need confirmation on and ill submit it and disperse the fg
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Dec 1 2013 05:26pm


30fg for this one
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Dec 1 2013 05:27pm
(-5,5) should fit then
#8

11.6 hours
q20
/e as we got diff answers i'll detail :
if h is the number of hours requiered for B to clean the land, then we have:
7/h + 7/(h+6) = 1
solving for h gives 11.6

This post was edited by HbSoe on Dec 1 2013 05:35pm
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Dec 1 2013 05:30pm
Quote (HbSoe @ Dec 1 2013 11:27pm)
(-5,5) should fit then


perfect for the last one i got 10.9 hours not sure if its right though
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