Inorganic Chemistry Help - Topic

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Nov 23 2013 07:37am

Quote (fingerling @ Nov 22 2013 09:42pm)

Identify the strongest type of intermolecular force (dipole-dipole, london dispersion, ion-dipole, ion-ion, hydrogen bond) in the following substances:

Ar (london)

HCl (dipole-dipole)

HF (would be hydrogen, but if we're looking at only one HF molecule, can we say it is hydrogen bonding, or would it be dipole-dipole? since there isn't other HF atoms for H bonding to occur)

CaCl2 (ion-ion)

CH4 (london)

CO (dipole-dipole)

CHCl3 (london)

added a hint

This post was edited by ArnoldChlamydia on Nov 23 2013 07:37am

fingerling

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#12

Nov 23 2013 01:12pm

Quote (ArnoldChlamydia @ Nov 23 2013 08:37am)

added a hint

Imm too dumb... Please explain.

nlin

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#13

Nov 23 2013 03:05pm

Quote (fingerling @ Nov 23 2013 12:12pm)

Imm too dumb... Please explain.

What do you think are the differences between Intermolecular and intramolecular forces

fingerling

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#14

Nov 23 2013 03:10pm

Quote (nlin @ Nov 23 2013 04:05pm)

What do you think are the differences between Intermolecular and intramolecular forces

Inter is molecule to molecule attraction and intra is within one molecule. I don't see how this helps me. It seems to me he should have wrote intra instead of inter?

I don't know. I asked for he help and so far I've had two wrong replies and two riddles.

Haaaaalp

fingerling

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#15

Nov 25 2013 02:51pm

That it ? Test timr

ArnoldChlamydia

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#16

Nov 25 2013 03:21pm

intermolecular forces are between more than 1 of the molecule

ie. HF is hydrogen bonding because theres many HF molecules in a solution of HF

so H from 1 HF would form hydrogen bonds with F from another HF:

H-F - - - H-F - - - H-F - - - H-F

etc.

sry for the delay i've been away and i thought my hint would be enough

gl in the test!

This post was edited by ArnoldChlamydia on Nov 25 2013 03:22pm

fingerling

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#17

Nov 25 2013 03:33pm

UOTE=ArnoldChlamydia,Nov 25 2013 04:21pm]intermolecular forces are between more than 1 of the molecule

ie. HF is hydrogen bonding because theres many HF molecules in a solution of HF

so H from 1 HF would form hydrogen bonds with F from another HF:

H-F - - - H-F - - - H-F - - - H-F

etc.

sry for the delay i've been away and i thought my hint would be enough

gl in the test![/QUOTE]

I know that numerous HF molecules together make a h bond. My question is one single solitary HF molecule. NOT MULTIPLE.

I also need the other questions answered. Not sure why you guys can't read the post before you type

ArnoldChlamydia

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#18

Nov 25 2013 03:51pm

Quote (fingerling @ Nov 22 2013 09:42pm)

Identify the strongest type of intermolecular force (dipole-dipole, london dispersion, ion-dipole, ion-ion, hydrogen bond) in the following substances:

Ar (london) - correct because Ar hass full octet etc.

HCl (dipole-dipole) - correct because Cl- isnt electronegative enough to form h-bonds

HF (would be hydrogen, but if we're looking at only one HF molecule, can we say it is hydrogen bonding, or would it be dipole-dipole? since there isn't other HF atoms for H bonding to occur) - read the question it asks for intermolecular forces

CaCl2 (ion-ion) - yep because Ca+ + 2Cl- --> CaCl2

CH4 (london) - yep because zero net charge due to symmetry of td molecule

CO (dipole-dipole) yep because yep

CHCl3 (london) nope because dipole-dipole

edited.

your first post is hardly a question

fingerling

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#19

Nov 25 2013 04:01pm

Quote (ArnoldChlamydia @ Nov 25 2013 04:51pm)

edited.

your first post is hardly a question

OK thank you.

cialda

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#20

Nov 25 2013 05:32pm

Quote (fingerling @ Nov 25 2013 03:33pm)

Quote (ArnoldChlamydia @ Nov 25 2013 04:21pm)

gl in the test!

I know that numerous HF molecules together make a h bond. My question is one single solitary HF molecule. NOT MULTIPLE.

I also need the other questions answered. Not sure why you guys can't read the post before you type

the question asks about intermolecular forces, hence there are multiple HF molecules. if you are looking at one molecule of each, there would be no intermolecular forces, not just Hbonding, since the single molecule would have nothing to interact with.

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