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Aug 29 2013 12:50pm
Quote (saber_x3 @ Aug 29 2013 02:23pm)
No, n is the number of measured data points, the average is a calculated value
n=3
sqrt[[(5.2-5.17)^2  + (5.15 -5.17)^2 + (5.15 -5.17)^2]  *(1/(3-1))]


Ah, alright.
Another question, with regards to the uncertainties on the averages - are my values correct? I had briefly talked to my professor before class had started, and he made some mention of my average uncertainty as being 0.15, not 0.05. Granted, the uncertainty will grow as I work my way through this, but I just want to double check what this value should actually be.

In my post in #9, should that average value be 5.17 +/- 0.15 or is it fine as is?
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