Yeah
I had something like uh
|(3-x) (1 / (x-1) )| < e/2
I am wondering if I can just suppose at this part that d < 1 and then say that -1 < 3 - x < 1
or if it has to be in the |x-3| form before I can do that
but afaik that is impossible because 'e' cannot be negative, and the only way to make 3-x the other way is multiplying by negative 1
This post was edited by Eep on Oct 2 2011 08:31pm