Basically speaking I have to work out the reaction forces and perform a checksum to show that my answer is correct. I am having a complete brain fart and have an answer sat in front of me, but want to see if someone else can do it too, so that I can ensure I have the correct result!

If I can get an answer in the next hour, that is correct, and another can confirm is correct, then I shall give 200fg

This post was edited by Kalms on Nov 26 2014 01:06pm

moment about Wf
2.8 (.9) +1.6(Wr) =7(.9)
wr=2.3625 kn
Vertical forces
Wf +Wr =2.8 +7
wf=7.4375 kn

This post was edited by saber_x3 on Nov 26 2014 01:14pm

This doesnt seem correct to me because it is in complete static equilibrium, which means that the vertical forces must summate to 0N.

EDIT: Looking at the recalculated one and going to run through it myself. See if anyone else gets it to be the same. Cheers.

This post was edited by Kalms on Nov 26 2014 01:17pm

I got exactly what he did.

Wr = 2.3625
Wf = 7.4375

This post was edited by Dontrunaway on Nov 26 2014 01:24pm

What I am trying to get here, is how it is actually worked out in stages if that is ok, should have been more clear, but as this is an assignment question, and I was in hospital when we covered this subject, I am really struggling with it.

Thanks so far though! Just need to make sure I get the right steps in as it is a 'Show your working' assignment

This is absolutely awesome man! Was just working this out again myself. I got the wrong answer because for some reason, I was thinking that the Wf part would mean that anything to the left of it would not be counted. But this is not the case!

As I have to perform a checksum, would it be better for me to work out the moments individually, then add them up to get the total forces in the upwards direction, so that I can then make that my checksum if it cancels out to 0N?

This post was edited by Kalms on Nov 26 2014 02:16pm

Equilibrium in 2-D:
Sum of moments at any given point must be zero.
Summation of y forces must be zero.
Summation of x forces (there are none) must be zero.

You take the moment about one of the unknowns to get the other unknown.
Then you use summation of y to get the other unknown.

e/ Cantilevered beams are still beams.

This post was edited by Dontrunaway on Nov 26 2014 02:23pm

The funny thing is, I actually understand cantilevered beams, because they are literally one end with forces on. I get confused when I should or should not include something into a moment of a static beam, suspended at multiple positions, even though I know deep down that I am just meant to include everything. The logical part of my head is kicking in and saying 'The other wheel will take the force' but it doesn't... And I get myself tied in knots working it out because I was not in the lectures working it out!

First year student as a Mechanical Engineer ftw...

I just graduated with a degree in aerospace/mechanical engineering.

It doesn't get any easier than statics. :\ It's a long road.

This post was edited by Dontrunaway on Nov 26 2014 02:40pm