Determine the require size of one rectangular floor , of a floor joist system. The beams are spaced 16 inch on centers. The width of the beam is 1.5in and the span length is L = 16ft between centers of bearing. Assume that the area of bearing at the support is 1.5in x 2in.

loads and allowable strength values are also given and deflectin limits too.

what im confused about is the terminology used in the problem. what does it mean spaced 16 inch on centers? and the area of the cross section isn't given..

It means if you were to measure from the center of one beam to the center of another, they would be 16 inches apart.
You can measure from the edge of the beam to the same edge of the other beam, should equal the same distance.

ok but its suppose to be a design of 1 beam.. so how do u put tat in context

----------------
|.......|.........|
|.......|.........| |
|.......|.........| 16 ft
|.......|.........| |
----------------
-16in-|-16in-|



doesn't seem like the height of beams are given

This post was edited by saber_x3 on Sep 23 2014 11:25pm

yea it wasn't given. is what u drew, suppose to be the cross section area?

no, rofl

google a floor joist
i drew the horizontal members

I assume what I did is correct. You did not provide a full problem statement.

Here

Bad problem considering floor joist beams don't lay the way it's intended in the problem.

16 in on centers is the distance of the parallel beams
Doesn't apply to your current problem
You know the length of the beam
You know the width
You have to find the height
basically a beam over 2 supports
----
I don't know what ll or dl is

This post was edited by saber_x3 on Sep 24 2014 04:25pm

live load and dead load probably.

wat about the area of bearing, will that be of any help?
How would I take account of the loads given..

Area of bearing information is given to you
I don't think you understand the geometry of the set up if you have any questions on that.
It's literally like a wooden beam with 2 flat supports on both ends.

If you say those are 2 different types of loads then ok
that makes sense, since the deflection formula given to you is for distributed load